SBI Clerk Prelims Reasoning Syllabus

The SBI Clerk Prelims Reasoning Syllabus comprises 35 questions that carry a total of 35 marks with 1 mark allotted for each question. The reasoning section of the SBI Clerk exam is a scoring paper which tests the knowledge of the candidates and their capability of solving the general ability problems, with their intelligence.

In simple terms, reasoning is the ability to understand and simplify the problem from the information provided in a twisted manner by applying logic, using the facts in place and verifying them. It is mainly associated with Maths, Science, different languages, etc.

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Important Topics of Reasoning Syllabus

Given below are the topics of the reasoning syllabus for SBI Clerk Prelims exam:

Logical Reasoning and Verbal Reasoning

  • Logical Reasoning: Deductive Reasoning, Inductive Reasoning and Abductive Reasoning
  • Verbal Reasoning: Proposition, Premise, Syllogism and Verbal Analogies

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Non- Verbal Reasoning

  • Symbol and their Relationship, Arithmetical Computation, Decision Making, Verbal and Figure classification, Verbal & Non-Verbal
  • Analytical function, Space Visualization, Judgment, Blood Relations
  • Assertion, Seating Arrangement, Input-Output, Coding-Decoding

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SBI Clerk Prelims Exam Pattern for Reasoning Section

Candidates should get acquainted with the SBI Clerk Prelims exam pattern of the Reasoning Syllabus before taking the exam:

  1. Comprises 35 questions.
  2. Sectional duration of the Reasoning part is 20 minutes
  3. Total marks is 35 marks
  4. 1 mark is awarded for every correct attempt
  5. 1/4th or 0.25 mark is deducted for every incorrect answer

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Important Bank Information:

Weightage of Questions in Reasoning Section

To get a better understanding of the importance of Reasoning syllabus for SBI Clerk Prelims exam, we have listed below the topic-wise expected number of questions in this section:

Reasoning Syllabus – SBI Clerk Prelims

Topics

Sub-Topics

Expected Number Of Questions

Logical Reasoning

Deductive Reasoning

2

Inductive Reasoning

0-4

Abductive Reasoning

0-2

Verbal Reasoning

Proposition

2

Premise

0-3

Syllogism

5

Verbal Analogies

0-3

Non-Verbal Reasoning

Symbol and their Relationship

0-5

Arithmetical Computation

0-5

Decision Making

4-8

Verbal and Figure classification

0-5

Verbal & Non-Verbal

0-4

Analytical function

5

Space Visualization

5-6

Judgment

0-2

Blood Relation

5

Assertion

4-6

Seating Arrangement

10

Input-Output

0-5

Coding-Decoding

5

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SBI Clerk Reasoning Books and Preparation Tips

The reasoning section of SBI Clerk Prelims exam is a time-consuming section. While preparing for the Reasoning syllabus of SBI Clerk exam, candidates should understand that a lot of practice is required to excel in this section. During the examination, they should be careful and attempt the easy and short questions first and then move on to the tough ones gradually.

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Here we bring forth a list of books that candidates can refer while prepping up for the SBI Clerk Reasoning section:

Best Reasoning Books for SBI Clerk Exam

Book Title

Author Name

A Modern Approach to Verbal and Non-Verbal Reasoning

R. S. Aggarwal

Analytical Reasoning

M. K. Pandey

How To Prepare For Data Interpretation and Logical Reasoning

Arun Sharma

Test of Reasoning

Edgar Thorpe

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Reasoning Questions and Answers (Practice)

Given below are some of the Reasoning questions and answers from different topics that we hope will prove beneficial for candidates preparing for SBI Clerk Preliminary exam.

Blood Relations:

Question 1 : Read the following information carefully and answer the questions given below:

There are six children playing football, namely

A, B, C, D, E, and F. A and E are brothers. F is the sister of E. C is the only son of A’s uncle. B and D are the daughters of the brother of C’s father.

Example 1:

How is C related to F?

  1. Cousin
  2. Brother
  3. Son
  4. Uncle

Example 2:

How many male players are there?

  1. One
  2. Three
  3. Four
  4. Five

Solution:

Family tree of six children playing football

Family tree of six children playing football

Explanation:

Example 1:

The data doesn’t specify whether C’father is a maternal uncle or paternal uncle to A. Hence it is represented as a triangle(unknown). From the diagram, it is clear that C is the Cousin of A who is the brother or sibling of F, hence C is the cousin of F. The correct answer is an option A.

Example 2:

There is a total of three male players and three female players. The male players are represented by a square, they are A, C, and E.

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Calendars:

Question 2: What day of the week was the 4th April 1994?

  1. Monday
  2. Tuesday
  3. Wednesday
  4. Thursday
  5. Friday

Solution:

The year 1994 till April 4th can be broken down as follows:

1600 + 300 + 93 + 4th April (from January to April in 1994)

The number of odd days in 1600 years is ‘0’ (zero) as it is a multiple of 400.

The number of odd days in 300 years is ‘1’.

To find the number of odd days in 93 years (1901 to 1993), divide the number 93 by 4 to find the number of leap years. 93 divided by 4 gives quotient as 23 which indicates that in 93 years there are 23 leap years and 70 ordinary years.

We know that an ordinary year and a leap year has one and two odd days each. Hence 70 ordinary year gives 70 odd days and 23 leap year gives 23*2 = 46 odd days. 70 + 46 = 116. Therefore a total of 116 odd days are present in 93 years. Dividing the number 116 by 7 we get 4 as the remainder. Therefore the total number of odd days in 93 years is 4.

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In the year 1994 till April 4th, only the first three months are over. January and March ahs three odd days each. And since 1994 is not a leap year, February has ‘0’ odd days. And the data is given as 4th April, so the four days of April are also considered as odd days of April.

In total = 3(Jan) + 0 (Feb) + 3(March) + 4 (April 1st to 4th April) = 10 odd days = which indicates 3 odd days when divided 10 by 7.

Total number odd days from each section = 0+1+4+3 = 8.

The number 8 is divided by 7, this results in remainder 1. The number 1 as remainder indicates its a Monday. Hence, the correct answer is option A.

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Simple Equation and Age Problems (Miscellaneous):

Question 3: Six years ago, the ratio of the ages of Nandan and Suraj was 6:5 Four years hence, the ratio of their ages will be 11:10 What is Suraj’s age at present?

A. 18

B. 17

C. 16

D. 15

Solution:

Let the age of Nandan and Suraj six years ago be 6x and 5x respectively. If the 6x and 5x are their ages ‘6’ years ago then after 4 years their ages will be (6x+ 10) and (5x +10) as there is a total gap of 10 years.

We know that after four years ratios of their ages 11:10

(6x+10):(5x+10) = 11:10

(6x+10)*10 = (5x+10)*11

60x+100 = 55x +110

60x-55x = 110-100

5x = 10

Therefore, x = 10/5 = 2

Hence, Suraj’s present age will be: (5x+6) = (5*2+6) = 16

Hence, the correct answer is option C.

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