Sri Aurobindo Integral Education & Research Centre School Sundargarh Orissa

School Name Sri Aurobindo Integral Education & Research Centre
Address At - Birmitrapur Sundargarh Orissa 770033 India
Head/Principal Sahadev Sahu (M.A. (Economics), B.Ed., M.Ed.)
Status Secondary School
Phone Number 0661-2610476
School Type Independent
CBSE Affiliation Type Provisional
CBSE Affiliation Period 1/4/2013 To 31/3/2018
Founded In 1988
Fax Number Not Specified
Email saierc (dot) brmp (at) yahoo (dot) co (dot) in
Opening Date 4/17/1988 12:00:00 Am
School Trust Sri Aurobindo Study Circle
School Category Co-Educational
Total Classrooms 8
Land Area Meters: 8146.3219332Acres: 2.013Built-up Area: 2469Ground Area: 3478
Students Nursery-LKG: N/AI-V: 236VI-VIII: 63IX-X: N/AXI-XII: N/A
Nearest Railway Station Birmitrapur S.E.Rly. (In Kilometres: 3)
Nearest Police Station Birmitrapur S.E.Rly.Birmitrapur (In Kilometres: 1)
Nearest Bank State Bank Of India (In Kilometres: 1)
Swimming Pool
Indoor Games
Dance Rooms
Music Rooms
Health Check-up
Description Sri Aurobindo Integral Education & Research Centre located in At - Birmitrapur is a Co-Educational Secondary School institution affiliated to the Central Board of Secondary Education (CBSE) on Provisional basis since 1988. The school has been operating officially under the trust/society Sri Aurobindo Study Circle. The school is equipped with 8 class rooms and all essential facilities. If you're looking for details in admission/application forms, fees, school timings, vacations/holidays schedule or facilities provided, kindly visit the relevant department of the school.

NOTE: The data available with us about Sri Aurobindo Integral Education & Research Centre is maintained by Central Board of Secondary Education (CBSE) at We represent the same facts here in a user-friendly way.

Practise This Question

A uniform chain of length l is placed on the table in such a manner that its l' part is hanging over the edge of table without the chain sliding. If the coefficient of friction between the chain and the table is μ  then find the maximum length of chain l' that can hang without the entire chain slipping.