<div style="clear:both"/>               <div class="line description">                      <!-- Ask a question with input field -->                      <style type="text/css"><![CDATA[      #getconnect{          background-image: -moz-linear-gradient(top, #ffffff, #e6e6e6);          background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#ffffff), to(#e6e6e6));          background-image: -webkit-linear-gradient(top, #ffffff, #e6e6e6);          background-image: -o-linear-gradient(top, #ffffff, #e6e6e6);          background-image: linear-gradient(to bottom, #0088CC, #0044CC);          background-color: #006DCC;          border-color: rgba(0, 0, 0, 0.1) rgba(0, 0, 0, 0.1) rgba(0, 0, 0, 0.25);      }  ]]></style><p>                          </p><div align="justify"><b>Electrical </b>is the branch of physics dealing with electricity, electronics and electromagnetism. Electrical formulas play a great role in finding the parameter value in any electrical circuits.    Most commonly used electrical formulas are formulas related to voltage, current, power, resistance etc. <br/><br/><b/><span class="content_color"><b>Volt </b></span>is a unit of electrical potential or motive force - potential is required to send one ampere of current through one ohm of resistance. <span class="content_color"><b>Watt  </b></span>is a unit of electrical energy or power - one watt is the product of one ampere and one volt - one ampere of current flowing under the force of one volt gives one watt of energy<br/><br/>Below are given some commonly used Electrical formulas which may be helpful for you.<br/><br/></div><table border="1" cellspacing="0"><tbody><tr><td class="" align="center"><span class="content_color">Quantity </span></td> <td align="center"><span class="content_color">Formula  </span></td>             <td align="center">  <span class="content_color">Unit </span>  <br/></td>                        </tr><tr><td align="center">Charge</td> <td align="center"><br/>Q = C $\times$ V<br/><br/></td> <td align="center">  Coulomb   <b>(C)</b></td>  </tr><tr><td align="center">Capacitance </td> <td> <br/><div align="center">                    C = <span class="content_latex">$\frac{Q}{V}$</span>                            </div></td> <td align="center"> Farad <b>(F)</b></td>  </tr><tr><td align="center">Inductance<br/></td> <td align="center">   <br/><div align="center">                    V<sub>L</sub> = - L  <span class="content_latex">$\frac{di}{dt}$</span>                                         <br/></div></td> <td align="center">Henry <b>(L  or H)</b></td>  </tr><tr><td align="center">Voltage </td> <td align="center"><br/>V = I R<br/><br/></td> <td align="center">Volt <b>(V)</b></td>  </tr><tr><td align="center">Current</td> <td><div align="center"><br/>I = <span class="content_latex">$\frac{V}{R}$<br/><br/></span></div></td> <td align="center">Ampere <b>(A)</b></td>  </tr><tr><td align="center">Resistance</td> <td><div align="center"><br/>R = <span class="content_latex">$\frac{V}{I}$<br/><br/></span></div></td> <td align="center">ohm <b>($\omega$)</b></td>  </tr><tr><td align="center">Power</td> <td align="center"><br/>P = VI<br/><br/></td> <td align="center">Watt <b>(W)</b></td>  </tr><tr><td align="center">Conductance</td> <td><div align="center"> <br/>G = <span class="content_latex">$\frac{1}{R}$<br/><br/></span></div></td> <td align="center">mho <b>($mho$)</b></td>  </tr><tr><td align="center">Impedance</td> <td align="center"><br/>Z<sup>2</sup> = R<sup>2</sup> + (x<sub>L</sub> -  x<sub>c</sub>)<sup>2<br/><br/></sup></td> <td align="center">ohm <b>($\omega$)</b></td>  </tr><tr><td align="center">Resonant Frequency</td> <td align="center"> <br/>f = <span class="content_latex">$\frac{1}{2 \pi \sqrt{LC}}$<br/></span><br/></td>             <td align="center">Hertz <b>(Hz)</b></td>                        </tr></tbody></table><br/><div align="justify"><b>Electrical Formulas</b> helps us to calculate the parameters related to electricals in any electrical components.<br/><br/></div>                                      </div>                    <div style="padding: 5px 30px;">                                               </div>                <div style="clear:both;height:1px;"> </div>              <div class="line description">                                      <div class="btitlehold">                          <h2 class="blocktitle">Electrical Problems</h2>                          <a class="backtotop" href="#top" name="electrical-problems">Back to Top</a>                          <br style="clear:both"/></div>                      <div align="justify">Problem based on Electrical which may be helpful for you are given below.<br/></div>                        <div class="questionBox"><h3>Solved Examples</h3>                                <div class="question">                                      <b>Question 1: </b>A wire carrying a current of 4 Amperes is having resistance of 5 $\omega$. Calculate the potential difference across its ends.<br/><b> Solution: </b>                                          <div class="solution">  <br/>Given: Current I = 4 A,        <br/>          Resistance R = 5 $\omega$<br/>The Potential difference is given by V = IR <br/>                                                      = 4 A $\times$ 5 $\omega$                                        <br/>                                                      = 20 V.<br/> <br/><br/></div>                                 </div>                                  <div class="question">                                      <b>Question 2: </b>Calculate the charge across the capacitor 5mF and the voltage applied is 25 V.<br/><b> Solution: </b>                                          <div class="solution">  <br/>Given: Capacitance of the capacitor C = 5 mF, <br/>          Voltage applied V = 25 V,<br/>The Charge across the capacitor is given by Q = CV                                               <br/>                                                                   = 5 mF $\times$ 25 V                                               <br/>                                                                   = 125 $\times$ 10<sup>-3</sup> C                                               <br/>                                                                   = 0.125 C.<br/> <br/><br/></div>                                 </div>                          </div>             </div>                           <div style="margin:5px 0px 5px 0px;box-shadow:2px 2px #d8d8d8;">                                <!-- Bottom of the Page Ads for MCPW Subdomains -->                 <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-9036831849580519" data-ad-slot="8504651656" data-ad-format="auto"/>                           </div>          </div>