Frustum of a Regular Pyramid Formula
The frustum is a pyramid that is the result of chopping off the top of a regular pyramid. That is the reason why it is called a truncated pyramid.
The distance between the base and the top of the pyramid is the height and is denoted by h. Similarly, it has a slant height that is denoted by “s” and two bases (top and bottom), whose area is defined by
We need to find the lateral surface area and the volume of Frustum of regular pyramid formula.
\[\large V=\frac{h(B_{1}+B_{2}+\sqrt{B_{1}B_{2}})}{3}\]
\[\large S=\frac{s(P_{1}+P_{2})}{2}\]
Here,
S = Lateral Surface Area
h=Height
s = Slant height
V=Volume
Solved Examples
Question: Find the volume of a frustum of a regular pyramid whose area of bases are 9 cm2, 10 cm2 respectively and height is 9 cm.
Solution:
Given
B1 = 9 cm2
B2 = 10 cm2
h = 9 cm
Volume formula,
V =
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