# Gay Lussac Law Formula

In 1808, the French chemist Joseph Louis Gay-Lussac reported the results of new experiments together with a generalization known today as Gay-Lussac’s law of combining gases.

**The volume of gas is directly proportional to the Kelvin temperature if the volume is kept constant.**

_{V1}= original volume

_{V2}= final volume

_{1}= original temperature (K)

_{2}= final temperature (K)

Gay-Lussac’s Law is applicable only to gases. The volumes of liquids or solids involved in the reactants or products are not governed by Gay Lussac’s law.

## Gay Lussac Law Formula Solved Examples

Some of the solved problems based on Gay Lussac Law Formula are given below.

**Question 1: **What is the volume of a quantity of a gas at 27^{o}C if its volume was 400mL at 0^{o}C? The pressure remains constant.**Solution:**

Since the temperature increased, the volume increased. Here we must use a temperature factor greater than 1, that is 300/273

^{o}C + 273 = 300 K

^{o}C + 273 = 273 K

**Question 2: **Solve Gay-Lussac’s Law to get an expression for the unknown volume. Substitute the appropriate data into the formula.

_{1}= 400mL

_{2}= ? mL

_{1}= 0

^{o}C

_{2}= 27

^{o}C

**Solution:**

_{1}= 400mL

_{2}= ? mL

_{1}= 0

^{o}C + 273 = 273K

_{2}= 27

^{o}C + 273 = 300K

_{2}= $\frac{(400 mL)(300 K)}{273 K}$

_{2}= 438 mL