Selina Solutions Concise Mathematics Class 6 Chapter 22 Simple (Linear) Equations Exercise 22(B) contains answers designed by expert faculty, in accordance with the exam pattern of the ICSE. The solutions are solved in a stepwise manner, as each step carries marks in the final examinations. Our set of faculty at BYJU’S prepare 100% accurate answers to boost the academic performance of students. Provided here, Selina Solutions Concise Mathematics Class 6 Chapter 22 Simple (Linear) Equations Exercise 22(B), free PDF links.
Selina Solutions Concise Mathematics Class 6 Chapter 22: Simple (Linear) Equations Exercise 22(B) Download PDF
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Access Selina Solutions Concise Mathematics Class 6 Chapter 22: Simple (Linear) Equations Exercise 22(B)
Exercise 22(B)
1. Solve:
(i) 2x + 5 = 17
(ii) 3y – 2 = 1
(iii) 5p + 4 = 29
(iv) 4a – 3 = – 27
(v) 2z + 3 = – 19
Solution:
(i) 2x + 5 = 17
2x = 17 – 5
2x = 12
x = 12 / 2
We get,
x = 6
Therefore, the value of x = 6
(ii) 3y – 2 = 1
3y = 1 + 2
3y = 3
y = 3 / 3
We get,
y = 1
Therefore, the value of y = 1
(iii) 5p + 4 = 29
5p = 29 – 4
5p = 25
p = 25 / 5
We get,
p = 5
Therefore, the value of p = 5
(iv) 4a – 3 = – 27
4a = – 27 + 3
4a = – 24
a = – 24 / 4
We get,
a = – 6
Therefore, the value of a = – 6
(v) 2z + 3 = – 19
2z = – 19 – 3
2z = – 22
z = – 22 / 2
We get,
z = – 11
Therefore, the value of z = – 11
2. Solve:
(i) x / 3 – 5 = 2
(ii) y / 2 – 3 = 8
(iii) z / 7 + 1 = 2 (1 / 2)
(iv) a / 2.4 – 5 = 2.4
(v) b / 1.6 + 3 = – 2.5
Solution:
(i) x / 3 – 5 = 2
x / 3 = 2 + 5
x / 3 = 7
x = 7 × 3
We get,
x = 21
Hence, the value of x = 21
(ii) y / 2 – 3 = 8
y / 2 = 8 + 3
y / 2 = 11
y = 11 × 2
We get,
y = 22
Hence, the value of y = 22
(iii) z / 7 + 1 = 2 (1 / 2)
This can be written as,
z / 7 + 1 = 5 / 2
z / 7 = 5 / 2 – 1
z / 7 = (5 – 2) / 2
We get,
z / 7 = 3 / 2
z = (3 / 2) × 7
On calculating, we get
z = 21 / 2
z =
Hence, the value of z =
(iv) a / 2.4 – 5 = 2.4
a / 2.4 = 2.4 + 5
a / 2.4 = 7.4
a = 7.4 × 2.4
We get,
a = 17.76
Hence, the value of a = 17.76
(v) b / 1.6 + 3 = – 2.5
b / 1.6 = – 2.5 – 3
b / 1.6 = -5.5
b = – 5.5 × 1.6
We get,
b = – 8.8
Hence, the value of b = – 8.8
3. Solve:
(i) – 8m – 2 = – 10
(ii) 4x + 2x = 3 + 5
(iii) 4x – x + 5 = 8
(iv) 6x + 2 = 2x + 10
(v) 18 – (2a – 12) = 8a
Solution:
(i) – 8m – 2 = – 10
– 8m = – 10 + 2
– 8m = – 8
m = – 8 / – 8
We get,
m = 1
Therefore, the value of m = 1
(ii) 4x + 2x = 3 + 5
6x = 8
x = 8 / 6
We get,
x = 4 / 3
x =
Therefore, the value of x =
(iii) 4x – x + 5 = 8
3x = 8 – 5
3x = 3
x = 3 / 3
We get,
x = 1
Therefore, the value of x = 1
(iv) 6x + 2 = 2x + 10
6x – 2x = 10 – 2
On further calculation, we get
4x = 8
x = 8 /4
x = 2
Therefore, the value of x = 2
(v) 18 – (2a – 12) = 8a
18 – 2a + 12 = 8a
30 = 8a + 2a
30 = 10a
a = 30 / 10
We get,
a = 3
Therefore, the value of a = 3
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