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Question

3.12g of oxygen is adsorbed on 1.2g of platinum metal. The value of oxygen adsorbed per gram of the adsorbent at 1atm and 300K in L is _______.

[R=0.0821LatmK-1mol-1]


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Solution

Answer : (2)

  1. Moles of O2 =3.1232=0.0975
  2. Volume of O2 =nRTP=(0.0975×0.082×300)/1
  3. Volume of O2 =2.3985L2.4L
  4. Volume of O2 absorbed per gram of platinum is =2.42=2

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