A 5.82g silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver is precipitated as AgCl . The AgCl precipitate weighs 7.20g . The percentage of silver in the coin is;

A. 60.3%

B. 80%

C. 93.1%

D. 70%

Solution: (C)

Weight of AgCl precipitated = 7.2 g

Weight of Ag in the precipitate = (108 g) / (143.5 g) × (7.2 g) = 5.42 g

= % of silver in the coin = (5.42g) / (5.82g) × 100 = 93.1%

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