A boy pushes a box of mass 2 kg with a force \(\vec{F}=(20\hat{i}+10\hat{j})N\) on a frictionless surface. If the box was initially at rest, then __________m is displacement along the x-axis after 10 s.

Answer: 500

\(\vec{F}=(20\hat{i}+10\hat{j})N\)

Fx = 20 N

Fy = 10 N

ax = Fx/M = 20/2 = 10 m/s2

Displacement on x-axis is

Sx = uxt + ½ axt2

Sx = 0 × 10 + ½ × 10 ×(10)2

= 500  m

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