A bullet fired into a fixed wooden block loses half of its velocity after penetrating 40 cm. It comes to rest after penetrating a further distance of

1) 22/3

2) 40/3

3) 20/3 

4) 22/5

5) 26/5

Answer: 2) 40/3

Solution:

(from A to B)

v2 = u2 – 2as

⇒ (v/2)2 = v2 – 2a x 40 

v2/4 – v2 = -80a

⇒ a = 3v2/320

(from B to C)

v2 = u2 – 2as

⇒ 0 = (v/2)2 – 2 x (3v2/320) x X

⇒ X = (40/3) cm

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