A bullet of mass 10 g moving with 300 m/s hits a block of ice of mass 5 kg and drops dead. The velocity of ice is

1) 50 cm/s

2) 60 cm/s

3) 40 cm/s

4) 200 cm/s

Answer: 2) 60 cm/s

Solution:

Applying law of conservation of linear momentum

m1u1+m2u2=m1v1+m2v2

10-2 x 300 + 5 x 0 = 10-2 x 0 + 5v2

5v2= 3

v2= (3/5) m/s = 60 cm/s

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