A car moving with a velocity of 10 m/s can be stopped by the application of constant force F in a distance of 20 m. If the velocity of the car is 30 m/s, it can be stopped by this force in

1) (20/3)

2) 20 m

3) 60 m

4) 180 m

Answer: 4) 180 m


Final velocity is zero and the acceleration is negative

Using the equation of motion v2 = u2 – 2as

0=(10)2−2(F/m)20 ——(1)

0=(30)2−2(F/m)d ——–(2)

Solving equa (1) and (2)


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