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Question

A charged particle going around in a circle can be considered to be a current loop. A particle of mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field B. The magnetic moment of this moving particle:


A

mv2B2B2

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B

-mv2B2πB2

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C

-mv2B2B2

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D

-mv2BB2

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Solution

The correct option is C

-mv2B2B2


Step 1 : Given data

Mass of the particle =m

Charge of the particle =q

Magnetic field =B

image

Step 2 : To find the magnetic moment

Magnetic moment

M=iA

A=πr2M=qT×πr2=qπr22πrv=qvr2M=qv2×vmqBM=mv22B

The direction of magnetic moment M is opposite to magnetic field

M=mv22B×-B=-mv2B2B2

Hence the magnetic moment M=-mv2B2B2

Therefore the correct answer is Option C


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