CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A circle passes through the points (0,0) and (0,1) also touches the circle x2+y2=16.

The radius of the circle is


A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
E

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2


Explanation for correct option:

Step 1. Assume the general equation of the circle :

Let the equation of the circle be

x2+y2+2gx+2fy+c=0

Step 2. Apply the given condition :

The circle x2+y2+2gx+2fy+c=0 passes through the (0,0) and (0,1).

∴c=0 and 1+2f+c=0

⇒c=0,f=-12

The circle x2+y2+2gx+2fy+c=0 touches the circle x2+y2=16

∴g2+f2=4±g2+f2-c⇒g2+14=4±g2+14⇒4=2g2+14⇒g2=4-14⇒g2=154⇒g=±152

Step 3. Calculate the center and radius of the circle :

Therefore, the coordinate of the center is =±152,12

And radius g2+f2-c=154+14

=164=4=2

Hence, the correct option is (B).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition and Standard Forms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon