A compound has the molecular formula, X4O6. If 10 g of X4O6 has 5.72 g X , then calculate atomic mass of X.

A. 32 u

B. 64 u

C. 67 u

D. 98 u

Solution: (A)

Molecular weight of X4O6 = (4a + 96)

As such, (4a + 96)g X4O6 contains X = 4a g

Therefore, 10g of X4O6 contains X = 4a × 10 / 4a + 96

5.72 = 4a × 10 / 4a + 96

22.88a + 549.12 = 40a

17.12a = 549.12

a = 32.07 amu

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