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Question

A dice is thrown twice. The probability of getting 4,5 or 6 in the first throw and 1,2,3,or 4 in the second throw is


A

1

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B

13

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C

736

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D

None of these

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Solution

The correct option is B

13


Explanation for the correct answer:

Step 1: Find the probability of getting 4,5 or 6 in the first throw.

We have been given that, a dice is thrown twice.

We need to find the probability of getting 4,5 or 6 in the first throw and 1,2,3,or 4 in the second throw

Let event A: getting 4,5 or 6 in first throw.

P(A)=36

Step 2: Find the probability getting 1,2,3, or 4 in the second throw.

Let event B: getting 1,2,3, or 4 in second throw.

P(B)=46

Step 3: Find the required probability.

The probability of getting 4,5 or 6 in the first throw and 1,2,3,or 4 in the second throw would be,

=P(A)×P(B)=36×46=13

Therefore, option (B) is the correct answer.


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