A man slides down on a telegraphic pole with an acceleration equal to one-fourth of acceleration due to gravity. The frictional force between man and pole is equal to in terms of man's weight w

1) W/4

2) W/2

3) 3W/4

4) W

Answer: 3) 3W/4

Solution:

Given

a = g/4

ma = W – f

Frictional force f = W – ma

W is the weight of the man = mg

Therefore, f = mg – m(g/4)

= 3w/4

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