A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be:

1) √2 a

2) a/√2

3) 2a

4) 2√2 a

Answer: (2)

In FCC, one of the faces is like

JEE Main 2017 Chemistry April Set A Paper Question 5

By △ABC,

2a2 = 16r2

r2 = (1 / 8) a2

r = 1 / 2√2 a

Distance of closest approach = 2r = a / √2

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