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Question

A particle moves so that S=6+48t-t3. The direction of motion reverses after moving a distance of


A

63

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B

104

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C

134

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D

288

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Solution

The correct option is C

134


Step 1: Given data.

Distance covered by particle,S=6+48t-t3

Step 2: Finding the distance after the direction of motion reverses.

Since, we have,

S=6+48t-t3

We know that,

v=dSdt v=velocity

v=48-3t2 …….i

Now, when the direction reversed then.

v=0

48-3t2=0 Fromequationi

t=-4 or t=4

Again,

At t=4.

S=6+48×4-43

S=134

Hence, option C is correct.


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