wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A person throws two dice, one the common cube, and the other a regular tetrahedron, the number on the lowest face being taken in the case of tetrahedron. The probability that the sum of the numbers appearing on the dice is 6, will be


A

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

13

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

16

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

16


Explanation for the correct option:

Step 1: Find the number of cases when the sum is 6:

Given: A tetrahedron and a regular cube.

So, possible cases of (tetrahedron cube, common cube)=(1,5),(2,4),(3,3)(4,2)

Hence, n(E)=4

Step 2: Find the total number of cases for tetrahedron and regular cube:

The total number of possible cases will be the product of the total outcomes of both cases.

n(s)=6×4=24

Step 3: Find the probability of the sum as 6:

Divide possible cases by the total number of cases to get the probability.

Probability, p=424=16

Hence, option (C) is the correct answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Compound Events [ P(A or B), P( A and B) ]
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon