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Standard XII

Physics

Motional EMF

A solid metal...

Question

A solid metal cube of edge length $2 c m$ is moving in the positive $y$ direction at a constant speed of $6 m / s$ . There is a uniform magnetic field of $0.1 T$ in the positive $Z$ direction. The potential difference between the two faces of the cube perpendicular to the $X$ axis, is:

$1 m V$

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$6 m V$

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$12 m V$

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$2 m V$

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Solution

The correct option is C
$12 m V$

Step 1: Given data
Length of the cube $= 2 c m$
Speed of the cube $= 6 m / s$
Magnetic field $= 0.1 T$
Step 2: To find the potential difference
The potential difference between two faces perpendicular to X-axis will be
$l . (\overset{⇀}{V} \times \overset{⇀}{B}) = 2 \times 0.1 \times 6 \times 10^{- 2} m = 1.2 \times 10^{- 2} = 12 \times 10^{- 3} = 12 m V$
Hence the potential difference between the two faces is $12 m V$
Therefore, the correct answer is Option C.

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A solid metal cube of edge length 2cm is moving in the positive y direction at a constant speed of 6m/s. There is a uniform magnetic field of0.1T in the positive Z direction. The potential difference between the two faces of the cube perpendicular to the X axis, is:

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