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Question

An electric dipole of moment vector p=-i^-3j^+2k^×10-29cm is at the origin 0,0,0. The electric field due to this dipole atr=(i^+3j^+5k^) is parallel to [Note that r.p=0]


A

i^-3j^-2k^

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B

-i^-3j^+2k^

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C

i^+3j^-2k^

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D

-i^+3j^-2k^

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Solution

The correct option is C

i^+3j^-2k^


Step 1. Given data

An electric dipole of the moment, p=-i^-3j^+2k^×10-29cm

Position vector, r=i^+3j^+5k^

r.p=0

Step 2. Finding the electric field, E

r.p=0 This means the field is along the tangential direction and the dipole is perpendicular to the radius vector. Since the electric field and dipole are along the same line, we can write

E=λp [Where λis an arbitrary constant]

E=-i^-3j^+2k^×10-29×-1×1029

E=i^+3j^-2k^

Therefore, the correct option is C.


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