An object is gently placed on a long converges belt moving with 11 ms-1. If the coefficient of friction is 0.4, then the block will slide in the belt up to a distance of

1) 10.21 m

2) 15.125 m

3) 20.3 m

4) 25.6 m

Answer: 2) 15.125 m

Solution:

a = mg = 0.4 x 10 = 4m/s2

u = 11m/s

v = 0

v2 = u2 + 2as

0 = (11)2 + 2(-4) x s

s = (11 x 11)/8 = 15.125 m

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