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Question

Consider the following reaction:

MnO4-+5H++8e-Mn2++4H2O, E°=1.51V

The quantity of electricity required in Faraday to reduce five moles of MnO4- is ___________.


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Solution

The above question can be solved as:

Step 1: The reaction given is: MnO4-+8H++5e-Mn2++4H2O

Step 2: In this reaction, 1mole MnO4- reduces to form Mn2+and for this reaction 5Fe- are required.

MnO4-Mn2++7+2

Step 3: Now,

1moleMnO4-=5F5moleMnO4-=5×5F=25F

Therefore, the quantity of electricity required to reduce five moles of MnO4- is 25F.


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