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Question

For a chemical reaction, Keqis100at300K , the value of ΔGoisxRJouleat1atmpressure. Find the value of x. (Use ln 10=2.3)?


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Solution

Keq is the equilibrium constant for reversible chemical reaction.

Step 1: Given Keq = ΔG°=xRJoule, R=8.31Jmol-1K-1 , ln10=2.3

Step 2: The formula used ΔG°=-RTln(Keq)

Step 3: ΔG°=-RTln(Keq)=-R(300)ln(100)

=-R(300)(2)ln(10)=-R(300)(2)(2.3)

=ΔG°=-1380R

-xR=-1380R

The value of x for the chemical reaction is x=1380Joule


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