From a balloon rising vertically upwards 5 ms-1 at stone is thrown up at 10 ms-1 relative to the balloon. Its velocity w.r.t. ground after 2 s is (assume, g = 10 ms-2)

1) zero

2) -5 ms-1

3) 10 ms-1

4) 20 ms-1

Answer: 2) -5 ms-1

Solution: 

From the equation of motion, we get

v=u+gt

u=10+5=15m/s

g=10m/s2

t=2s

Therefore, v=15−(2×10)=−5m/s

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