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Question

How can we prepare 0.1 N HCl solution?


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Solution

Step1: Molar mass for HCl = 36.4611g/mol

The volume will be in 1 litre and the specific gravity of HCl is 1.189

Step 2: Volume= Mass/Density

Step3:Compound required in grams = (0.1 N)(36.4611)(1Litre) = 3.3461

Volume of concentrated acid required = (3.3461)/l0.375×1.189)=8.1774ml

Therefore,8.1774 ml of 37.5% concentrated HCl is required to prepare 0.1 M HCl


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