Question

How many radial nodes are present in $5\mathrm{f}$ orbital ?

Answer 1

Radial nodes: It is a spherical surface where the probability of finding an electron is zero.

1. The formula$=\mathrm{n}-\mathrm{l}-1$ Where, Radial nodes Where $\mathrm{n}=$ Principal quantum number, $\mathrm{l}=$Azimuthal quantum number.
2. The number of radial nodes increases with a principal quantum number.
3. The value of ‘$\mathrm{n}$’ is a natural integer $1,2,3,4,5,6,7$.
4. The value of $‘\mathrm{l}’$is a whole integer.
5. For 5f orbitals, $\mathrm{n}=5$ and $\mathrm{l}=3$
6. Therefore, the number of a radial node will be $\mathrm{n}-\mathrm{l}-1=5-3-1=1$

Therefore, the number of Radial nodes in $\mathbf{5}\mathbf{f}$ orbitals is $\mathbf{1}$.