Question

How many words can be formed from the letters of the word ‘COURTESY’, whose first letter is ‘C’ and the last letter is ‘Y’.

• A. $6!$
• B. $8!$
• C. $2(6!)$
• D. $2(7!)$

Answer 1

The correct option is A

$6!$

Find arrangement:

Given word is ‘COURTESY’ in which ‘C’ and ‘Y’ is fixed in their places i.e. first and last

Remaining letter of the ‘COURTESY’ word are ‘O, U, R, T, E, & S’

Total number of place that remaining letter can be place is $6$

Therefore the number of arrangement of the remaining words with no repetition $6!or1\times 6!\times 1=720$

Hence, the correct option is $\left(A\right)$