If 3x+2(x+1)(2x2+3)=A(x+1)+Bx+C2x2+3, then A+C-B=
0
2
3
5
Step 1. Find the value of A+C-B:
Given, 3x+2(x+1)(2x2+3)=Ax+1+Bx+C2x2+3
⇒ 3x+2=A(2x2+3)+(Bx+C)(x+1)
Put x=–1
3(-1)+2=A(2(1)+3)+(B(-1)+C)(-1+1)
⇒ -3+2=A(5)
⇒ -1=A(5)
⇒ -15=A
Step 2. On comparing the coefficients, we get
2A+B=0
⇒ B=-2A
=25
3A+C=2
⇒ C=2+35
=135
∴A+C–B=(–15)+135–25=2
Hence, Option ‘(B)’ is Correct.
If (x+1) is a factor of the polynomial (2x2+kx) then the value of k is (a) -2 (b) -3 (c) 2 (d)3
The anti derivative of equals
(A) (B)
(C) (D)