If a,b and c are in GP, then the equation ax2+2bx+c=0 and dx2+2ex+f=0 have a common root, if da,eb and fc are in
AP
HP
GP
None of these
Explanation for the correct option:
Given that, a,b,c are in GP, then
b2=ac
⇒b=ac
ax2+2bx+c=0
⇒ax2+2√acx+c=0
⇒ (√ax+√c)2=0
⇒ x=-ca
∵ax2+2bx+c=0 and dx2+2ex+f=0 have common root.
then, x=-ca must satisfy dx2+2ex+f=0
⇒d×ca–2eca+f=0
⇒ da–2e√ac+fc=0
⇒ 2eb=da+fc
∴da,eb,fc are in AP.
Hence, Option ‘A’ is Correct.
If a,b,c are in G.P, then the equation ax2 + 2bx + c = 0 and dx2 + 2ex + f = 0 have a common root if da,eb,fc are in