1) 0
2) 1
3) a.b
4) b.c
Answer: (1) 0
Solution: Given, vectors (a + b), (b + c) and (c + a) are coplanar
Therefore,
(a+b) [(b+c) x (c + a)] = 0
⇒ (a+b) (b x c + b x a + c x c + c x a) = 0
⇒ (a + b) (b x c + b x a + c x a) = 0
⇒ a.(b x c) + a.(b x a)+ a.(c x a) + b.(b x c) + b.(b x a) + b.(c x a) = 0
⇒ [a b c] + 0 + 0+ 0+0 = 0
⇒ [a b c] = 0