a) 2
b) 3
c) -1
d) 1
Solution:
Vector PM and (
\(\begin{array}{l}2\hat{i}-2\hat{j}-\hat{k}\end{array} \)
) are perpendicular.
⇒ (2λ-2)2+(1-2λ)(-2)+(3-λ) (-1) = 0
⇒ 4λ-4+4 λ-2+λ-3 = 0
⇒ 9λ = 9
⇒ λ = 1
⇒ M(1,1,-1)
Now, P’ = 2M-P
= 2(1,1,-1)-(1, 2, -3)
= (1, 0, 1)
a+b+c = 2
Answer: a
