If ax = by = cz = dw, then the values of x [(1 / y) + (1 / z) + (1 / w)] is

1) loga (abc)

2) loga (bcd)

3) logb (cda)

4) logc (dab)

Solution: (2) loga (bcd)

ax = by = cz = dw

log ax = log by

x log a = y log b

(x / y) = [log b] / [log a] = loga b

loga b = x / y

loga c = x / z

loga d = x / w

loga (bcd) = loga b + loga c + loga d

= (x / y) + (x / z) + (x / w)

= x [(1 / y) + (1 / z) + (1 / w)]

loga (bcd) = x [(1 / y) + (1 / z) + (1 / w)]

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