Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

If ax = by = cz and b2 = ac, then the value of y is

1) 2xz/(x+z)

2) xz/2(x-z)

3) xz/2(z-x)

4) 2xz/(x-z)

 

Solution:

Let ax = by = cz = k

So a = k1/x

b = k1/y

c = k1/z

Given b2 = ac

k2/y = k1/xk1/z

k2/y = k1/x + 1/z

2/y = 1/x + 1/z

2/y = (z+x)/xz

y = 2xz/(z+x)

Hence option (1) is the answer.

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