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Question

If I1=03πf(cos2x)dx and I2=0πf(cos2x)dx, then


A

I1=I2

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B

3I1=I2

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C

I1=3I2

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D

I1=5I2

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Solution

The correct option is C

I1=3I2


Explanation for correct option:

Find the relation:

Given that,

I1=03πf(cos2x)dx and

I2=0πf(cos2x)dx

Now,

I1=03πf(cos²x)dx=30πf(cos²x)dx[0nTf(x)dx=n0Tf(x)dx,f(x)isperiodicwithT]=3I2

Hence, the correct option is C.


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