CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If I=01dx1+xπ2, then


A

loge2<I<π4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

loge2>I

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

I=π4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

I=loge2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

loge2<I<π4


Explanation for correct option:

Find the relation:

Since, x(0,1), then

x2<xπ2<x1+x2<1+xπ2<1+x[add1andtakereciprocal]11+x2>11+xπ2>11+x0111+x2dx>0111+xπ2dx>0111+xdx[tan-1x]01>I>[In|1+x|]01π4>I>In2-In1π4>I>In2

Hence, the correct option is A.


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Higher Order Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon