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Question

Suppose a refrigerator does minimum possible work in converting 100 grams of water at 0°C to ice. How much heat (in calories) is released to the surroundings at a temperature of 27°C (Latent heat of ice = 80 Cal/gram) to the nearest integer?


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Solution

Solution:

Latent heat of fusion:

  • Latent heat of fusion, also known as enthalpy of fusion, is the amount of energy that must be supplied to a solid substance (typically in the form of heat) in order to trigger a change in its physical state and convert it into a liquid (when the pressure of the environment is kept constant).
  • For example, the latent heat of fusion of one kilogram of water, which is the amount of heat energy that must be supplied to convert 1 kg of ice without changing the temperature of the environment (which is kept at zero degrees celsius) is 333.55 kilojoules.

Q=mL=8000cal

Q2=W+Q1Coefficientofperformance(COP)=Q1W=Q1Q2-Q1=T1T2-T1Q1W=273300-273Q1W=27327W=27273Q1W=27273×80×100Q2=27273×80×100+80×100Q2=791.208+8000Q2=8791.208cal

The amount of heat released into the surroundings at a temperature of 27°C is 8791 calories.


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