Solution:
Given x = (-3+i√3)/2
= (-1+i√3)/2-(1/1) = ω-1 [since ω = (-1+i√3)/2]
(x2+3x2)2(x2+3x+1)
(x2+3x2)2(x2+3x+1)
= [(ω-1)2+3(ω-1)2][(ω-1)2+3(ω-1)+1]
= (ω2+ω-2)2(ω2+ω-1)
= (-1-2)2(-1-1) (since ω2 +ω = -1
= (-3)2(-2)
= -2×9
= -18
Hence option (3) is the answer.
