If [x] stands for the greatest integer function then the value of 15+11000+15+12000+......+15+9991000 is:
199
201
202
200
Explanation for the correct option.
15+r1000 will be equal to 1 for x=800.
So, we can say that
15+r1000=1800≤x<99900<x<800
Number of terms in the interval 800≤x<999 is 200.
So,
15+11000+15+12000+......+15+9991000=0+(200×1)=200
Hence, option D is correct.
loge(n+1)−loge(n−1)=4a[(1n)+(13n3)+(15n5)+...∞] Find 8a.