CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Young's double slit experiment with slit separation 0.1mm, one observes a bright fringe at angle 1/40rad by using light of wavelength λ1. When the light of wavelength λ2 is used a bright fringe is seen at the same angle in the same setup. Given that λ1 and λ2 are in visible range (380nmto740nm), their values are:


A

380nm,525nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

625nm,500nm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

380nm,500nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

400nm,500nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

625nm,500nm


Step 1: Given:

Angle, θn=140

Wavelengths: λ1 and λ2

Slit separation, d=0.1mm=0.1×10-3m

Step 2: Find the equation for λ:

The angle at which the bright fringe is formed is given by,

θn=nλd140=nλ0.1×10-3nλ=0.25×10-5mλ=0.25×10-5n

Step 3: Substitute various values of n

n=1,λ=2500nmn=2,λ=1250nmn=3,λ=833.3nmn=4,λ=625nmn=5,λ=500nmn=6,λ=416.6nmn=7,λ=357.14nm

Therefore, option B is the correct option.


flag
Suggest Corrections
thumbs-up
22
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon