Solution:
1+ z+ z3 + z4 = 0
=> (1+z)+z3(1+z) = 0
=> (1+z3)(1+z) = 0
z = -1
z3 = -1
z = -1, – ω, -ω2 are cube roots of unity
So these are the vertices of an equilateral triangle.
Hence option (3) is the answer.
Solution:
1+ z+ z3 + z4 = 0
=> (1+z)+z3(1+z) = 0
=> (1+z3)(1+z) = 0
z = -1
z3 = -1
z = -1, – ω, -ω2 are cube roots of unity
So these are the vertices of an equilateral triangle.
Hence option (3) is the answer.