Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

In Young's double-slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them.

In Young’s double-slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by monochromatic light of 5890 Å is:

a. 1178 × 10-6m

b. 1178 × 10-9m

c. 5890 × 10-7m

d. 1178× 10-12m

Answer:(a)

D = 0.5 m

d = 0.5 mm

λ = 5890Å

Distance between first and third bright fringe = 2β = 2λD/d

= 2 × 5890 × 10-10 × 0.5/(0.5×10-3)

= 1178 × 10-6 m

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