In Young's double slit experiment if the slits widths are in the ratio 1 : 9, the ratio of the intensities at minima to that at maxima will be

(a) 1
(b) 1/9
(c) 1/4
(d) 1/3

Solution:
Answer: (c) 1/4
Intensity of fringe is directly proportion to width os the slits.

Therefore, I2/I1 = W2/W1 = 1:9

or I1 = 9I2

The maximum intensity and minimum intensity are Imax = (√I1 + √I2)2

and Imin = (√I1 – √I2)2 respectively.

So, Imax = 16 I2

and Imin = 4 I2

Therefore, Imin/Imax = 1/4

Was this answer helpful?

 
   

2.5 (5)

(7)
(4)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

Ask
Question