Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

-π/2π/2([x] - [sin⁡x ])dx = (Where [.] represents G.I.F)

a. -2

b. 1

c. 0

d. -1

Solution:

Answer: (c)

I = ∫-π/2π/2([x] – [sin⁡x ])dx

Using the property ∫-aa f(x)dx = ∫0a f(x)dx + ∫0a f(-x)dx

I = ∫0π/2 ([x] + [-x] )dx – ∫0π/2([sin ⁡x] + [-sin ⁡x])dx

= 0

Hence option c is the answer.

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