Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

Light of wavelength 6000 A falls on a single slit of width 0.1 mm. The second minimum will be formed for the angle of diffraction of

(a) 0.06 rad

(b) 0.05 rad

(c) 0.12 rad

(d) 0.012 rad

Solution:

Answer: (d)

Wavelength = λ = 6000 = 6 x 10-7 m

d = 0.1 x 10-3 m

n = 2

The angle of diffraction = nλ/d

= [2×6 x 10-7]/[1×10-4]

= 0.012 rad

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