Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

limx→0 [(√a + x - √a - x) / (4x)] =

1) 1/2√a

2) 4/4√a

3) 1/3√a

4) 2/√a

Solution: (2) 4/4√a

\(\begin{array}{l}\begin{array}{l} \lim _{x \rightarrow 0}\left(\frac{\sqrt{a+x}-\sqrt{a-x}}{4 x}\right) \\ \text { Apply } L \text { ‘ hospital rule }\left(\frac{0}{0} \text { form }\right) \\ \lim _{x \rightarrow 0} \frac{\frac{1}{2 \sqrt{a+x}}-\frac{1 \times-1}{2 \sqrt{a-x}}}{4 \times 1} \\ \Rightarrow \frac{\frac{1}{2 \sqrt{a+0}}+\frac{1}{2 \sqrt{a-x}}}{4} \Rightarrow \frac{\frac{1}{2 \sqrt{a}}+\frac{1}{2 \sqrt{a}}}{4}\\ \Rightarrow \frac{4}{4 \sqrt{a}} \end{array}\end{array} \)

Was this answer helpful?

 
   

2.5 (2)

(5)
(6)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published.

*

*

Ask
Question