Re (1-i)^2/(3-i) is equal to (1) -1/5 (2) 1/5 (3) 1/10 (4) -1/10

Solution:

(1-i)²/(3-i) = (1-2i-1)/(3-i)

= -2i/(3-i)

Multiply numerator and denominator with (3+i)

= -2i(3+i)/(3-i)(3+i)

= (-6i+2)/(9+1)

= (2-6i)/10

= (1-3i)/5

Real part is ⅕.

Hence option (2) is the answer.