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Question

The reaction of an inorganic Sulphite X with dilute H2SO4 generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound Z. Y and Z, respectively, are :


A

SO2and NaHSO3

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B

S and Na2SO3

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C

SO2 and Na2SO3

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D

SO3 and NaHSO3

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Solution

The correct option is A

SO2and NaHSO3


Explanation for Correct answer:

Option (A) SO2and NaHSO3

  • The reaction of Sodium sulphite (Na2SO3) with dilute Sulphuric acid(H2SO4) generates a compound of Sulphur dioxide(SO2).

Na2SO3(s)Sodiumsuphite+H2SO4(aq)dil.SulphuricacidH2O(l)Water+SO2(g)Sulphurdioxide

  • The reaction of Sulphur dioxide(SO2) with (NaOH) gives Sodium sulphite (Na2SO3).

SO2(g)Sulfurdioxide+NaOH(aq)SodiumhydroxideNa2SO3(aq)Sodiumsulphite

  • The reaction of Sodium sulphite(Na2SO3) with Sulphur dioxide(SO2) and water afford the compound Sodium bisulfite(NaHSO3).

SO2(g)Sulfurdioxide+Na2SO3(s)SodiumsulphiteNaHSO3(s)Sodiumbisulphate+H2O(l)Water

  • Therefore, X is Na2SO3, Yis SO2and Z is NaHSO3.
  • Hence correct option.

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