Rolle's theorem is not applicable to the function f (x) = |x| for -2 ≤ x ≤ 2 because

1) f is continuous for -2 ≤ x ≤ 2

2) f is not derivable for x = 0

3) f(-2) = f(2)

4) f is not a constant function

Solution: (2) f is not derivable for x = 0

(1) continuous on x ∈ R

(2) not differentiable (sharp point) at x = 0

(3) f (2) = f (- 2)